Respuesta :
Answer:
For a: The number of moles of air present in the RV is 0.047 moles
For b: The number of molecules of gas is [tex]2.83\times 10^{22}[/tex]
Explanation:
- For a:
To calculate the number of moles, we use the equation given by ideal gas follows:
[tex]PV=nRT[/tex]
where,
P = pressure of the air = 1.00 atm
V = Volume of the air = 1200 mL = 1.2 L (Conversion factor: 1 L = 1000 mL)
T = Temperature of the air = [tex]37^oC=[37+273]K=310K[/tex]
R = Gas constant = [tex]0.0821\text{ L. atm }mol^{-1}K^{-1}[/tex]
n = number of moles of air = ?
Putting values in above equation, we get:
[tex]1.00atm\times 1.2L=n_{air}\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 310K\\n_{air}=\frac{1.00\times 1.2}{0.0821\times 310}=0.047mol[/tex]
Hence, the number of moles of air present in the RV is 0.047 moles
- For b:
According to mole concept:
1 mole of a compound contains [tex]6.022\times 10^{23}[/tex] number of molecules.
So, 0.047 moles of air will contain [tex](0.047\times 6.022\times 10^{23})=2.83\times 10^{22}[/tex] number of gas molecules.
Hence, the number of molecules of gas is [tex]2.83\times 10^{22}[/tex]
