Answer:
The minimum temperature of the hot reservoir = 231.25 °C
Explanation:
η₁ = (1- T(c)/T(h)) × 100 ............. equation 1
Where η₁ = efficiency of the heat engine in percentage, T(c) = Temperature at which the low temperature reservoir operates, T(h)) =Temperature at which the high temperature reservoir operates.
Making T(h) the subject of the equation in equation 1
T(h) = T(c)/ {1-(η₁ /100)}
where η₁ = 41.2%, T(c) = 23.5 °C = 23.5 + 273 =296.5 K
∴T(h) = 296.5/{1-(41.2/100)}
T(h) = 296.5/(1- 0.412)
T(h) = 296.5/0.588
T(h) =504.25 K
Convert to temperature in Celsius
T(h) = 504.25 - 273 =231.25 °C
The minimum temperature of the hot reservoir = 231.25 °C
