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pressure A vertical piston cylinder device contains a gas at an unknown pressure. If the outside pressure is 100 kPa, determine (a) the pressure of the gas if the piston has an area of 0.2 m2 and a mass of 20kg. Assume g = 9.81 m/s2. (b) What-if Scenario: What would the pressure be if the orientation of the device were changed and it were now upside down

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Answer:

Explanation:

When Cylinder is vertical Let gas pressure inside is [tex]P_1[/tex] and atmospheric Pressure be

[tex]P_0=100 KPa[/tex]

Area of Piston [tex]A=0.2 m^2[/tex]

mass of Piston [tex]m=20 kg[/tex]

from FBD

[tex]mg+P_0A=P_1A[/tex]

[tex]P_1=P_0+\frac{mg}{A}[/tex]

[tex]P_1=100+\frac{20\times 9.8}{0.2}[/tex]

[tex]P_1=100+0.98[/tex]

[tex]P_1=100.98 KPa[/tex]

(b)If cylinder is upside down

From FBD

[tex]mg+P_2A=P_0A[/tex]

[tex]P_2=-\frac{mg}{A}+P_0[/tex]

[tex]P_2=100-\frac{20\times 9.8}{0.2}[/tex]

[tex]P_2=100-0.98=99.02 KPa[/tex]

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