The flowers of the bunchberry plant open with astonishing force and speed, with pollen grains accelerating from rest to 7.5 m/s. a. What impulse is delivered to a 1.0 * 10-10 kg pollen grain? b. What is the average force if this impulse is delivered in 0.30 ms? c. How does this force compare to the weight of the pollen grain?

Respuesta :

Answer:

a) J=[tex]7.5*10^{-10}[/tex]

b) F = [tex]2.5*10^{-6}N[/tex]

c) The force is 2551.02 times bigger than the weight of the pollen grain.

Explanation:

a) we know that the impulse J is equal to:

J =[tex]MV_f-MV_i[/tex]

where M is the mass, [tex]V_f[/tex] is the final velocity and [tex]V_i[/tex] the initial velocity. So, replacing values, we get:

J =[tex](10^{-10})(7.5m/s)-(10^{-10}(0)[/tex]

J =[tex](10^{-10})(7.5m/s)[/tex]

J=[tex]7.5*10^{-10}[/tex]

b) We know that the force is equal to:

F = J/t

where J is the impulse and t the time. So, replacing values, we get:

F = [tex]\frac{7.5*10^{-10}}{0.0003}[/tex]

F = [tex]2.5*10^{-6}N[/tex]

c) The weight W of the pollen grain is calculated as:

W = [tex]10^{-10}*9.8[/tex]

W = [tex]9.8*10^{-10}N[/tex]

So, if we compare the force and the weight of the pollen grain, we get:

[tex]\frac{2.5*10^{-6} }{9.8*10^{-10} } =2551.02[/tex]

it means that the force is 2551.02 times bigger than the weight of the pollen grain.

The Impulse ,Force and Weight  is mathematically given as

a)I=7.5e{-10}

b)F=2.5e^{-6}N

c)Wg=9.8e{-10}N

The Impulse ,Force and Weight

Generally the equation for the Impulse is mathematically given as

I=MVf-MVi

Therefore

I =(10^{-10})(7.5m/s)

I=7.5e{-10}

b)

Generally the equation for the Force is mathematically given as

F=I/t

F=7.5e{-10}/0.0003

F=2.5e^{-6}N

c)

The weight  of the pollen grain will be

Wg=M*g

Wg=10^{-10}*9.8

Wg=9.8e{-10}N

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