Answer:
Smallest collector size≈30[tex]m^{2}[/tex]
Explanation:
Daily sunlight intensity = 1400[tex]w/m^{2}[/tex].
For a collector of 24% efficiency, the absorption per day per [tex]m^{2}[/tex]
= 0.24*1400 = 336[tex]w/m^{2}[/tex].
For 8 hours, 25days of available sunlight, energy absorbed by collector per metre square , will be = 8* 25 *336 = 67200wh.
This is the amount of sunlight energy which will be trapped by 1[tex]w/m^{2}[/tex]. of collector in a month.
To find how many metre square of collector is required to get 2*[tex]10^{3}[/tex]kwh, we simply divide the required energy by the amount absorbed per square metre.
Smallest size of collected needed = [tex]\frac{2.00*1000*10^{3}}{67200}[/tex]
=29.76
≈30[tex]m^{2}[/tex]
