Iodine, I2(s), is more soluble in dichloromethane, CH2Cl2(l), than water because:
A. the intermolecular forces are similar in both dichloromethane and iodine.
B. the dipole-dipole forces in dichloromethane are much stronger than the dispersion forces in iodine.
C. Iodine is polar and dichloromethane has a large number of hydrogen bonds.
D. Both iodine and dichloromethane have strong, ion-dipole interactions

Respuesta :

Answer:

A. the intermolecular forces are similar in both dichloromethane and iodine.

Explanation:

Solubility is determined by the principle , "like dissolves like" .

i.e. , if a compound is polar then it will dissolve in a polar compound only , and

if a compound is non - polar then it will dissolve in a non - polar compound only .

As,

Non polar compounds , have similar interaction , and hence gets dissolved , and similarly ,

polar compounds have similar dipole - dipole interaction , and hence gets dissolved .

From the question ,

Iodine, I₂(s), is more soluble in dichloromethane, CH₂Cl₂(l) , as both are non - polar in nature and hence due to similar interaction , are soluble .

Water is polar in nature and therefore less soluble in Iodine, I₂(s) .

I2(s) is more soluble in dichloromethane, CH2Cl2(l), than water is because the intermolecular forces are similar in both dichloromethane and iodine.

What are intermolecular forces?

The term intermolecular forces refers to the forces that hold the molecules of a substance together in a particular state of matter. We must note that in chemistry like dissolve like.

The reason why I2(s) is more soluble in dichloromethane, CH2Cl2(l), than water is because the intermolecular forces are similar in both dichloromethane and iodine.

Learn more about intermolecular forces: https://brainly.com/question/11334504?