Acetaldehyde decomposes to methane and carbon monoxide according to the following balanced equation: CH3CHO → CH4 + CO In a particular experiment, the following kinetic data for the decomposition of acetaldehyde were obtained: Time(s) 0 1000 2000 3000 4000 [CH3CHO] (M) 0.3380 0.1341 0.0836 0.0608 0.0477 What is the value of the rate constant at the temperature of this experiment?

Respuesta :

Answer:

Explanation:

To obtain the rate constant it is necessary to determine the reaction order testing the lineality for each order using R² -The reaction order will be the R² with the R² ≈ 1-

The zero order is:  

[CH₃CHO] = [CH₃CHO]₀ - kt

For order 1 is:

ln[CH₃CHO] = ln[CH₃CHO]₀ - kt

For order 2 is:  

1/[CH₃CHO] = 1/[CH₃CHO]₀ - kt

The zero order graphing  [CH₃CHO] vs t gives a R² = 0,7507, that is the reaction is not order zero,

The graph of  ln[CH₃CHO] vs t gives a R² = 0,9251, thus reaction is not order 1.

The graph of  1/[CH₃CHO] vs t gives a R² = 1. The reaction is order 2

The lineal regression gives a formula of:

y = 0,0045x + 2,9575

Where the pendient is -k, that is k = -0,0045 M⁻¹s⁻¹

I hope it helps!