Answer:
(a).The wavelength of the waves is 0.624 m.
(b). The speed of the waves is 43.74 m/s.
(c). The fundamental frequency of the string is 14.02 Hz.
Explanation:
Given that,
length = 1.56 m
Frequency = 70.1 Hz
Number of loop = 5
(a). We need to the calculate the wavelength of the waves
Using formula of wave length
[tex]\lambda=\dfrac{2L}{n}[/tex]
Put the value into the formula
[tex]\lambda=\dfrac{2\times1.56}{5}[/tex]
[tex]\lambda=0.624\ m[/tex]
(b). We need to calculate the speed of the waves
Using formula of speed
[tex]v= \lambda\times f[/tex]
Put the value into the formula
[tex]v=0.624\times70.1[/tex]
[tex]v=43.74\ m/s[/tex]
(c). We need to calculate the fundamental frequency of the string
Using formula of fundamental frequency
[tex]f'=\dfrac{f}{n}[/tex]
Put the value into the formula
[tex]f'=\dfrac{70.1}{5}[/tex]
[tex]f'=14.02\ Hz[/tex]
Hence, (a).The wavelength of the waves is 0.624 m.
(b). The speed of the waves is 43.74 m/s.
(c). The fundamental frequency of the string is 14.02 Hz.