Answer:[tex]2T_0[/tex]
Explanation:
Given
object of mass is m is undergoing harmonic oscillations with time Period [tex]T_0[/tex]
Time Period of spring mass system
[tex]T=2\pi \sqrt{\frac{m}{k}}[/tex]
where k=spring constant
thus [tex]T_0=2\pi \sqrt{\frac{m}{k}}[/tex]
when mass is [tex]4m_0[/tex]
[tex]T'=2\pi \sqrt{\frac{4m}{k}}[/tex]
[tex]T'=2\times 2\pi \sqrt{\frac{m}{k}}[/tex]
i.e. [tex]T'=2T_0[/tex]
The new period of oscillation will be "2T₀".
A physical mechanism throughout which a measurement oscillates behind and in front of a mean value is placed at a single or maybe more distinctive harmonics or intervals.
According to the question,
The time period of spring mass system will be:
→ T = 2π[tex]\sqrt{\frac{m}{k} }[/tex]
here,
Spring constant = k
and,
→ T₀ = 2π[tex]\sqrt{\frac{m}{k} }[/tex]
By substituting "4m₀" in place of mass, we get
→ T' = 2π[tex]\frac{4m}{k}[/tex]
= 2 × 2π[tex]\sqrt{\frac{m}{k} }[/tex]
= 2T₀
Thus the response above is correct.
Find out more information about harmonic oscillations here:
https://brainly.com/question/17315536
