Answer:
This question is based on pigeonhole principle.
Let us assume there are 365 days in a year.
As there are 26 alphabets in English, we can say that there is a total of [tex]26^{3}[/tex] = 17576 possible initials for each person.
Hence, there will be [tex]17576\times365[/tex] = 6415240 possible triple initials and date of birth for each person.
As per pigeonhole principle, there are 36,000,000 pigeons.
Therefore, we can say that there will be [tex]\frac{36000000}{6415240}[/tex] = 5.6 ≈ 6 persons with the same initials who were born on the same day of the same month.
