Respuesta :
Answer:
Mass of CaO formed = 3.6106 g
Mass of [tex]Ca_3N_2[/tex] formed = 6.4170 g
Explanation:
The chemical reaction is shown below as:-
[tex]Ca+O_2\rightarrow 2CaO[/tex]
It will react with [tex]H_2O[/tex] and forms [tex]Ca(OH)_2[/tex]. The reaction is shown below as:-
[tex]CaO+H_2O\rightarrow Ca(OH)_2[/tex]
Overall reaction is;-
[tex]Ca+O_2+2H_2O\rightarrow 2Ca(OH)_2[/tex]
Let the mass of [tex]Ca[/tex] reacted to form [tex]CaO[/tex] = x g
Molar mass of [tex]Ca[/tex] = 40.078 g/mol
Moles of [tex]Ca[/tex]=[tex]\frac{x}{40.078}[/tex] moles
From the reactions shown above:-
1 mole of [tex]Ca[/tex] on reaction forms 2 moles of [tex]Ca(OH)_2[/tex]
Thus,
[tex]\frac{x}{40.078}[/tex] mole of [tex]Ca[/tex] on reaction forms [tex]\frac{2x}{40.078}[/tex] moles of [tex]Ca(OH)_2[/tex]
Moles of [tex]Ca(OH)_2[/tex] = [tex]\frac{2x}{40.078}[/tex] moles
Molar mass of [tex]Ca(OH)_2[/tex] = 74.093 g/mol
Mass of [tex]Ca(OH)_2[/tex] = Moles*Molar mass = [tex]\frac{2x}{40.078}\times 74.093[/tex] g
Also, given that mass of [tex]Ca(OH)_2[/tex] produced = 4.768 g
Thus,
[tex]\frac{2x}{40.078}\times 74.093=4.768[/tex]
x = 1.2895 g
Thus, mass of [tex]Ca[/tex] reacted to form [tex]CaO[/tex] = 1.2895 g
Mass of [tex]Ca[/tex] reacted to form [tex]Ca_3N_2[/tex] = 5.203g - 1.2895 g = 3.9135 g
Thus,
[tex]Ca+O_2\rightarrow 2CaO[/tex]
40 g of Ca on reaction forms 112 g of CaO
So,
1 g of Ca on reaction forms 112/40 g of CaO
1.2895 g of Ca on reaction forms [tex]\frac{112}{40}\times 1.2895[/tex] g of CaO
Mass of CaO formed = 3.6106 g
Also,
[tex]3Ca+N_2\rightarrow Ca_3N_2[/tex]
120 g of Ca on reaction forms 148 g of [tex]Ca_3N_2[/tex]
So,
1 g of Ca on reaction forms 148/120 g of [tex]Ca_3N_2[/tex]
5.203 g of Ca on reaction forms [tex]\frac{148}{120}\times 5.203[/tex] g of [tex]Ca_3N_2[/tex]
Mass of [tex]Ca_3N_2[/tex] formed = 6.4170 g
