Answer:
The total amount of soils that planter will hold to it is 590.45 inches³
Step-by-step explanation:
Given as :
The radius of the cone shape planter = r = 6.8 inches
The height of the cone shape planter = h = 12.2 inches
Let The total amount of soils that will hold to it = x cubic inches
Now, According to question
The total amount of soils that planter will hold to it = The volume of the cone
∵ The volume of cone = v = [tex]\dfrac{1}{3} \pi[/tex] r² h
where r is the radius
And h is the height
So, The total amount of soils that planter will hold to it = [tex]\dfrac{1}{3} \pi[/tex] r² h
or, x = [tex]\dfrac{1}{3}[/tex] × [tex]\pi[/tex] × r² × h
or, x = [tex]\dfrac{1}{3}[/tex] × 3.14 × (6.8)² inches × 12.2 inches
or, x = [tex]\dfrac{1}{3}[/tex] × 3.14 × 564.128 inches³
or, x = [tex]\dfrac{1}{3}[/tex] × 1771.361 inches³
or, x = [tex]\dfrac{1771.361}{3}[/tex] inches³
∴ x = 590.45 inches³
So, The total amount of soils that planter will hold to it = x = 590.45 inches³
Hence, The total amount of soils that planter will hold to it is 590.45 inches³ . Answer
