Respuesta :
Answer:
Step-by-step explanation:
v²-u²=2gh
initially u=0
v²=2gh
80²=2×32×h
h=(6400)/64=100 feet
The height from which the object has fallen if its velocity is 80 feet per second and g is approximately 32 feet per second squared is 100 ft.
What is projectile motion?
Projectile motion is the motion of the body, when it is thrown in the air taking the action of gravity on it.
The formula which gives the velocity v,i feet per second,of an object when it falls h feet accelerated by gravity g, in feet per second squared is,
[tex]v=\sqrt{2gh}[/tex]
The value of g, is approximately 32 feet per second squared and the velocity of the object is is 80 feet per second. Put this values in the above formula,
[tex]80=\sqrt{2(32)h}\\80=\sqrt{64h}\\80=\sqrt{8^2h}\\80=8\sqtrt{h}\\\sqrt{h}=\dfrac{80}{8}=10[/tex]
Squaring both side of the equation,
[tex]h=10^2\\h=100\rm\; ft[/tex]
Hence, the height from which the object has fallen if its velocity is 80 feet per second and g is approximately 32 feet per second squared is 100 ft.
Learn more about the projectile motion here;
https://brainly.com/question/24216590
