Answer:
44.01 grams of carbon dioxide will be formed
Explanation:
This is the balance equation:
2HCl (aq) + CaCO₃ (aq) → CaCl₂ (aq) + CO₂ (g) + H₂O (l)
Firstly, let's find out the moles for the salt, in the reactants.
Molarity . volume = Moles
1.2 mol/L . 1.25L = 1.5 moles
The stoichiometric amount of hydrochloric acid is 2.
Ratio between reactants is 2:1
If I have 2 moles of HCl, I need 1 mol of carbonate. I have 1.5 moles, so the salt is in excess and the limiting is the HCl.
Ratio between HCl and CO₂ is 2:1
If I have 2 moles of HCl, I make 1 mol of CO₂
The grams formed are just, the molar mass.
44.01 g
