Answer:
2.6 g of O₂ are present in the mixture
Explanation:
The molar fraction concept to solve this:
Partial pressure / Total pressure = Moles of a gas / Total moles in the mixture
720 mmHg / 942 mmHg = 0.764
This is the molar fraction of CO₂
Sum of molar fraction in mixture = 1
1 - 0.764 = 0.236
This is molar fraction of O₂
Molar mass CO₂ = 44.01 g/m
Moles CO₂ = 11.6 g / 44.01 g/m → 0.263 moles
Let's make the equation:
0.236 = x / x + 0.263
0.236 ( x + 0.263) = x
0.236x + 0.062 = x
0.062 = x - 0.236x
0.062 = 0.764x
0.062 / 0.764 = x → 0.081
These are the moles of O₂
Moles . molar mass = mass
0.081 m . 32g/m = 2.6 g
