Two people are talking at a distance of 3.0 m from where you are and you measure the sound intensity as 1.1 × 10-7 W/m2. Another student is 4.0 m away from the talkers. What sound intensity does the other student measure? Assume that the sound spreads out uniformly and undergoes no significant reflections or absorption.

Respuesta :

Answer:[tex]I_2=0.618\times 10^{-7} W/m^2[/tex]

Explanation:

Given

Distance between source and  receiver [tex]d_1=3 m[/tex]

Sound Intensity [tex]I_1=1.1\times 10^{-7} W/m^2[/tex]

Distance of of second observer [tex]d_2=4 m[/tex]

Intensity varies as

[tex]I\propto \frac{1}{d^2}[/tex]

using this

[tex]I=\frac{k}{d^2}[/tex]

[tex]\frac{I_1}{I_2}=\frac{d_2^2}{d_1^2}[/tex]

[tex]\frac{1.1\times 10^{-7}}{I_2}=\frac{4^2}{3^2}[/tex]

[tex]I_2=0.75^2\times 1.1\times 10^{-7}[/tex]

[tex]I_2=0.618\times 10^{-7} W/m^2[/tex]