Explanation:
Here momentum is conserved.
Momentum of bullet = Moment of man plus rifle after firing
Mass of bullet = 10 g = 0.01 kg
Speed of bullet = 500 m/s
Momentum of bullet = Mass of bullet x Speed of bullet = 0.01 x 500 = 5 kg m/s
Mass of man plus rifle = 70 kg
We need to find speed of man
Moment of man plus rifle after firing = Momentum of bullet = 5 kg m/s
Mass of man plus rifle x Speed of man = 5
70 x Speed of man = 5
Speed of man = 0.071 m/s
Final speed of the man = 0.071 m/s
The final speed of man will be "0.071 m/s".
According to the question,
Mass of bullet, m = 10 g or,
= 0.01 kg
Speed of bullet, s = 500 m/s
Man plus rifle's mass = 70 kg
Now,
The momentum of bullet will be:
= Bullet's mass × Bullet's speed
By substituting the values, we get
= 0.01 × 500
= 5 kg
hence,
The final speed be:
→ Man plus rifle's mass × Speed of man = 5
Or,
→ Speed = [tex]\frac{5}{Mass \ of \ man}[/tex]
By putting the values,
= [tex]\frac{5}{70}[/tex]
= 0.071 m/s
Thus the above answer is correct.
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