Answer:
- NH₄F (ammonium fluoride)
- K₂SO₄ (potassium sulfate)
Explanation:
Ammonium is a ion which is formed, when the ammonia takes a proton, from water. It's the conjugate strong acid, for the ammonia, which is a weak base.
This is the equilibrium
NH₄ ⇄ NH₃ + OH⁻
In the ammoniumm, N has 4 covalents bonds.
When ammonium reacts with F⁻, it forms this salt
NH₄⁺ + F⁻ → NH₄F
It can't be an equilibrium because the F⁻, is the conjugate weak base from the strong acid HF and it doesn't react. The ammonium fluoride is a ionic salt, which is completely soluble in water.
Sulfate ion is generated when the sulfuric acid is deprotonated. It's a weak acid when the first proton is released and so it forms bisulfate ion. This reaction has a litle Ka.
When this bisulfate ion is deprotonated again, it forms the sulfate ion.
Generally, the H₂SO₄ is treated as a strong acid.
The equations are this:
H₂SO₄ ⇄ H⁺ + HSO₄⁻ Ka
HSO₄⁻ → H⁺ + SO₄⁻²
As the sulfate has released 2 H⁺, when it reacts with K⁺, it forms also a ionic salt.
In this case there are 2 moles of K⁺.
K⁺ is the conjugate weak acid that comes, from a strong base (KOH)
It doens't react.
2K⁺ + SO₄⁻² → K₂SO₄
