A small motorboat travels 12 mph in still water. It takes 7 hours longer to travel 48 miles going upstream than it does going downstream. Find the rate of current. (Hint: 12+x= rate downstream and 12-x= rate upstream.)

Respuesta :

Answer:

Current rate of boat is 6.96 mph.

Step-by-step explanation:

Given:

Distance traveled = 48 miles.

Time to travel = 7 hours

Speed of the boat in still water = 12 mph

We need to find the Current rate.

Let current rate be x;

Downstream rate = [tex]12+x[/tex]

Upstream rate = [tex]12-x[/tex]

Now we know that Time is given by dividing Distance with Speed.

Hence Distance traveled is upstream and downstream.

Framing the equation we get;

[tex]\frac{48}{12-x}-\frac{48}{12+x} = 7[/tex]

Now taking LCM we get;

[tex]\frac{48(12+x)-48(12-x)}{(12+x)(12-x)}=7\\\\576+48x-576+48x=7\times (12+x)(12-x)\\96x=7\times(144-x^2)\\96x=1008-7x^2\\7x^2+96x-1008=0[/tex]

Now we will find the roots using quadratic formula.

a = 7 b =96 c =-1008

[tex]b^2-4ac=96^2-4\times7\times-1008\\b^2-4ac=9216+28224 = 37440\\\sqrt{b^2-4ac} = \sqrt{37440} =193.49[/tex]

Now Quadratic formula is given by;

[tex]x=\frac{-b\±\sqrt{b^2-4ac}}{2a}[/tex]

[tex]x_1= \frac{-96+193.49}{2\times7} = 6.96\\\\x_2= \frac{-96-193.49}{2\times7} = -20.67[/tex]

Now we have 2 values of x = 6.96 and x = -20.67

Since Speed of the boat cant be negative.

Hence we can say Current rate of boat is 6.96 mph