Answer:
Angular separation will be 0.250 miliradian
Explanation:
We have given distance between the screen and slits d = 1.8 mm
Wavelength of monochromatic light [tex]\lambda =450nm=450\times 10^{-9}m[/tex]
We have to find the angular separation
We know that angular separation is given by [tex]\Theta =\frac{\lambda }{d}[/tex]
So angular separation will be
[tex]\Theta =\frac{450\times 10^{-9}}{1.8\times 10^{-3}}=250\times 10^{-6}radian=0.250miliradian[/tex]
So angular separation will be 0.250 miliradian