Answer:
V₂ = 3.8 L
Explanation:
Given data:
Initial volume = 3 L
Initial temperature = 21°C
Final temperature = 100°C
Final volume = ?
Solution:
( 21=273 = 294 K)
(100+273 = 373 k)
According to charle's law,
V₁/T₁ = V₂/T₂
V₂ = V₁T₂/T₁
V₂ = 3 L× 373 K/ 294 K
V₂ = 1119 L. K / 294 K
V₂ = 3.8 L
