Chloe purchased some dried mango and dried kiwi to make some trail mix. The dried mango cost ​$2.11 per pound and the dried kiwi cost ​$5.07 per pound. If she spent ​$40.34 for 10 pounds of dried​ fruit, how many pounds of each fruit did she​ have?

Respuesta :

Answer:

Number of pounds of dried mangoes Chloe bought = 3.5

Number of pounds of dried kiwi Chloe bought bough = 6.5

Step-by-step explanation:

Total number of pounds of dried fruit purchased = 10

Let number of pounds of dried mango purchased = [tex]x[/tex]

Let number of pounds of dried kiwi purchased be = [tex]y[/tex]

Total weight of dried fruits purchased = [tex]x+y[/tex]

So, we have a sum equation as:

[tex]x+y=10[/tex]

Total cost of dried fruits = $40.34

Cost of a pound of dried mango = $2.11

Cost of [tex]x[/tex] pounds of dried mango in dollars can be given as = [tex]2.11x[/tex]

Cost of a dried kiwi = $5.07

Cost of [tex]y[/tex] pounds of dried kiwi in dollars can be given as = [tex]5.07y[/tex]

Total cost of dried fruits in dollars = [tex]2.11x+5.07y[/tex]

So, we have a cost equation as:

[tex]2.11x+5.07y=40.34[/tex]

The system of equations is :

A) [tex]x+y=10[/tex]

B) [tex]2.11x+5.07y=40.34[/tex]

Solving by substitution.

Rearranging equation A, to solve for [tex]y[/tex] in terms of [tex]x[/tex]

Subtracting both sides by [tex]x[/tex]

[tex]x+y-x=10-x[/tex]

[tex]y=10-x[/tex]

Substituting value of [tex]y[/tex] we got from A into equation B.

[tex]2.11x+5.07(10-x)=40.34[/tex]

Using distribution.

[tex]2.11x+50.7-5.07x=40.34[/tex]

Simplifying.

[tex]-2.96x+50.7=40.34[/tex]

Subtracting both sides by 50.7.

[tex]-2.96x+50.7-50.7=40.34-50.7[/tex]

[tex]-2.96x=-10.36[/tex]

Dividing both sides by -2.96.

[tex]\frac{-2.96x}{-2.96}=\frac{-10.36}{-2.96}[/tex]

∴ [tex]x=3.5[/tex]

We can plugin [tex]x=3.5[/tex] in the rearranged equation A to get value of [tex]y[/tex]

[tex]y=10-3.5[/tex]

∴ [tex]y=6.5[/tex]

So, number of pounds of dried mangoes Chloe bought = 3.5

Number of pounds of dried kiwi Chloe bought bough = 6.5