A 15.0-μF capacitor is charged by a 130.0-V power supply, then disconnected from the power and connected in series with a 0.280-mH inductor. Part A Calculate the oscillation frequency of the circuit. Express your answer with the appropriate units.

Respuesta :

The resonant frequency of a circuit is the frequency [tex]\omega_0[/tex] at which the equivalent impedance of a circuit is purely real (the imaginary part is null).

Mathematically this frequency is described as

[tex]f = \frac{1}{2\pi}(\sqrt{\frac{1}{LC}})[/tex]

Where

L = Inductance

C = Capacitance

Our values are given as

[tex]C = 15*10^{-6}\mu F[/tex]

[tex]L = 0.280*10^{-3}mH[/tex]

Replacing we have,

[tex]f = \frac{1}{2\pi}(\sqrt{\frac{1}{LC}})[/tex]

[tex]f = \frac{1}{2\pi}(\sqrt{\frac{1}{(15*10^{-6})(0.280*10^{-3})}})[/tex]

[tex]f= 2455.81Hz[/tex]

From this relationship we can also appreciate that the resonance frequency infers the maximum related transfer in the system and that therefore given an input a maximum output is obtained.

For this particular case, the smaller the capacitance and inductance values, the higher the frequency obtained is likely to be.