Respuesta :
Answer:
The measure of center would this student want his teacher to use is the
median[tex] = {\bf 75} [/tex]
Mean[tex] = {\bf 5} [/tex] , Mode[tex] ={\bf 82} [/tex] , Range[tex]={\bf40} [/tex] and Interquartile Range[tex] = {\bf 32} [/tex]
Step-by-step explanation:
Given Data set[tex] = 50,55,70,75,82,82,90 [/tex]
Number of elements in data set[tex] = 7 [/tex]
To find Mean
The ‘Mean” is the average of a set of numbers.
The "Mean" is computed by adding all of the numbers in the data together and dividing by the number of elements contained in the data set.
Mean[tex] = \frac{50 +55 +70 + 75 + 82 + 82 + 90} {7 } [/tex]
Mean[tex] = \frac{504}{7} [/tex]
Mean[tex] = 5 [/tex]
Median
The “Median” is the middle value of a set of ordered numbers.
Therefore Median[tex] =75 [/tex]
Mode
The "Mode" for a set of data is the value that occurs most often.
It is not uncommon for a data set to have more than one mode. This happens when two or more elements occur with equal frequency in the data set.
Therefore Mode[tex] =82 [/tex]
Range
The "Range" is the difference between the largest value and smallest value in a set of data.
Range[tex]= 90-50 [/tex]
Range[tex]= 40 [/tex]
Interquartile Range
The “Interquartile Range” is the difference between smallest value and the largest value of the middle 50% of a set of data.
The "Interquartile Range" is from Q1 to Q3:
To find the interquartile range of a set of data:
The cut the list into four equal parts
. The quartiles are the “cuts”
The interquartile range is the distance between the two middle sets of data
Interquartile Range[tex] = Q_3-Q_1[/tex]
Interquartile Range[tex] = 82-50[/tex]
Interquartile Range[tex] = 32[/tex]
