Answer:
Diameter will be 351.42 mm
Explanation:
We have given current flowing in the copper wire i = 310 A
Voltage drop across the wire V = 0.55 volt
We know that resistance is given by [tex]R=\frac{V}{i}=\frac{0.55}{310}=0.00177\Omega[/tex]
Length of the copper wire l = 1 m
Resisitivity of the copper wire [tex]\rho =1.72\times 10^{-8}\Omega m[/tex]
We know that resistance [tex]R=\frac{\rho l}{A}[/tex]
[tex]0.00177=\frac{1.72\times 10^{-8}\times 1}{A}[/tex]
[tex]A=969.4545\times 10^{-8}m^2[/tex]
As area [tex]A=\pi r^2[/tex]
[tex]3.14\times r^2=969.4545\times 10^{-8}[/tex]
[tex]r=17.57\times 10^{-4}m[/tex]
So diameter [tex]d=17.57\times 10^{-4}\times 2=35.142\times \times 10^{-4}m[/tex] = 351.42 mm
