Respuesta :

Answer:

the first five terms are

a1 = 6

a2 = 24

a3 = 60

a4 = 120

a5 = 210

Step-by-step explanation:

the experission used to find the five terms is

an = n3+ 3n2+ 2n

The first five terms of the sequence are 6, 24, 120, 720, 5040.

Sequence

A sequence is a series of numbers that follow a specific pattern or function.

A sequence can be finite or infinite.

Given to us

[tex]a_n=\dfrac{(n+3)!}{(n+3)}[/tex]

where n is the [tex]\bold{n^{th}}[/tex] term.

First-term, n=1,

[tex]a_1=\dfrac{(1+3)!}{(1+3)}=\dfrac{4!}{4} = 6[/tex]

Second-term, n=2,

[tex]a_2=\dfrac{(2+3)!}{(2+3)}=\dfrac{5!}{5} = 24[/tex]

Third-term, n=3,

[tex]a_3=\dfrac{(3+3)!}{(3+3)}=\dfrac{6!}{6} = 120[/tex]

Fourth-term, n=4,

[tex]a_4=\dfrac{(4+3)!}{(4+3)}=\dfrac{7!}{7} = 720[/tex]

Fifth-term, n=5,

[tex]a_5=\dfrac{(5+3)!}{(5+3)}=\dfrac{8!}{8} = 5040[/tex]

Hence, the first five terms of the sequence are 6, 24, 120, 720, 5040.

Learn more about Sequence:

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