Respuesta :
Answer:
1. HI
Explanation:
Electronegativity difference gives the magnitude of the bond polarity
Element Electronegativity
H 2.1
I 2.5
F 4
Cl 3
Br 2.8
Compound Polar bond
HI 2.5 - 2.1 = 0.4
HF 4 - 2.1 = 1.9
HCI 3 - 2.1 = 0.9
HBr 2.8 - 2.1 = 0.7
The least polar bond is found in a molecule of HI. Option 1 is correct.
The bond polarity between atomic elements or molecules is caused as a result of the interaction of bonds with differing electronegativities. As such, electronegativity is a determining factor for bond polarity.
On the periodic table, increasing electronegativity increase the bond polarity. Recall that, the electronegativity of an atomic element shows how the ability of how an atomic element can attract electrons to itself.
On the periodic table, as we go down the group, the electronegativity of atomic elements decreases. The order of electronegativity of the halogen family is:
- F > Cl > Br > I
As such, Iodine (I) has the least electronegativity in the given examples of the halogen family.
Therefore, we can conclude that the least polar bond is found in a molecule of HI since it has the least amount of electronegativity.
Learn more about electronegativity here:
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