Which represents the balanced double displacement reaction between Sodium Chloride (Na+Cl-) and Copper Sulfate (Cu2+(SO4)2-) ?


NaCl + Cu(SO4) --> Na2(SO4) + CuCl2


NaCl + Cu(SO4) --> Na(SO4) + CuCl


2NaCl + Cu(SO4) --> Na2(SO4) + CuCl2


NaCl + Cu(SO4) --> Cl(SO4) + NaCu

My answer was C I just wanna be sure

Respuesta :

Answer:

The balanced double displacement reaction is as follows.

[tex]2NaCl+CuSO_{4}\rightarrow Na_{2}SO_{4}+CuCl_{2}[/tex]

Explanation:

The given reactant has sodium,chloride and copper sulfate ions.

In the double displacement reaction, two ionic compounds exchange their cations.

Sulphate and chloride ions are cations these are exchanged sodium and copper elements.

Hence, the balanced double exchange reaction is as follows.

[tex]2NaCl+CuSO_{4}\rightarrow Na_{2}SO_{4}+CuCl_{2}[/tex]