The number of drinks bought is 10 and number of pretzels bought is 7
Let "d" be the number of drinks bought
Let "p" be the number of pretzels that Serenity bought
Cost of one drink = $5.50
Cost of one Pretzel = $3.25
Given that she’s bought $77.75 worth of drinks and pretzels
So we can frame a equation as:
number of drinks bought x Cost of one drink + number of pretzels bought x Cost of one Pretzel = 77.75
[tex]d \times 5.50 + p \times 3.25 = 77.75[/tex]
5.5d + 3.25p = 77.75 ----- eqn 1
Given that She bought 3 more drinks than pretzels
Number of drinks bought = 3 + number of pretzels bought
d = 3 + p
d - p = 3 --- eqn 2
Let us solve eqn 1 and eqn 2 to find values of "d" and "t"
Multiply eqn 2 by 3.25
3.25d - 3.25p = 9.75 ---- eqn 3
Add eqn 1 and eqn 3
5.5d + 3.25p = 77.75
3.25d - 3.25p = 9.75
(+) ---------------------------
8.75d = 87.5
d = 10
Substitute d = 10 in eqn 2
10 - p = 3
p = 7
Thus the number of drinks bought is 10 and number of pretzels bought is 7