contestada

A line is perpendicular to y = -x + 1
and intersects the point (-5,1).
What is the equation of this
perpendicular line?

Respuesta :

Answer:                                                                                                              The equation of the perpendicular line intersects the point (-5,1) is  y=x+6[/tex]

Step-by-step explanation:

step1:-

The standard form of slope - intercept form y=m x+c

Here m is called slope of the given line

C is called the y- intercept of the given line

Given equation of the straight line y=-x+1

comparing  the slope - intercept form y=m x+c

here m= -1 and c=1

step2:-

The equation of the perpendicular line is

[tex]y-{[y_{1}[/tex]} =\frac{-1}{m} (x-x_{1} )[/tex]

substitute m =  -1 and c =1 values  in equation

[tex]y-1 =\frac{-1}{-1} (x-(-5 )[/tex]

[tex]y-1 ={1} (x-(-5 )[/tex]

[tex]y=1+x+5

\\y=x+6[/tex]

step3:- The equation of the perpendicular line intersects the point (-5,1) is

y=x+6[/tex]

conclusion:-

The equation of the perpendicular line  is

y=x+6[/tex]