The force exerted by the track on the cart at the top of the loop is 220N.
Given :
Mass = 100 Kg
Radius = 3 m
Speed of cart = 6 m/sec
Solution :
Centripetal Force act on the cart therefore,
[tex]\rm \dfrac{mv^2}{r} = mg + N[/tex] --- (1)
Now put the values of m, g v and r in equation (1) we get,
[tex]\rm \dfrac{100\times 6^2}{3}= (100\times 9.8) + N[/tex]
[tex]\rm 1200 = 980+N[/tex]
N = 220N
The force exerted by the track on the cart at the top of the loop is 220N.
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