Answer:
[tex]E_a= 7 kJ/mol[/tex]
Explanation:
In this question we have to calculate the activation energy of the mechanism,we know that the mechanism of the reaction consists of pre equilibrium step with forward and reverse activation energies as 27 kJ mol−1 and 35 kJ mol−1 , respectively.
The slowest step is the rate determining step
Activation energy of the over all reaction is
[tex]E_a= E_{a2}+E_{a1}-E_{a(-1)}[/tex]
[tex]E_a= 15+27-35[/tex]
[tex]E_a= 7 kJ/mol[/tex]