Option D
Average score is 72.9 if he played 35 times a month
Solution:
Given that Lon Giron knows that his golf score is inversely related to the number of times he plays a week
[tex]\text {golf score} \space \alpha \frac{1}{\text { number of times he plays a week }}[/tex]
Given that When he plays 30 times a month, his average score is 85
Number of times he plays in a month = 30
average score = 85
[tex]85 \alpha \frac{1}{30}[/tex]
[tex]85=k \frac{1}{30}[/tex]
Where "k" represents constant of propotionality
[tex]k=30 \times 85=2550[/tex]
Thus we have found out value of k as 2550
Now if he played 35 times a month, we have to find his average score
Let the required average score be "a"
Let us use the value of "k"
[tex]\begin{array}{l}{a=k \frac{1}{35}} \\\\ {a=2550 \times \frac{1}{35}=72.85}\end{array}[/tex]
a = 72.85 ≈ 72.9
Thus average score is 72.9 if he played 35 times a month
