"A day care program has an average daily expense of $75.00. The standard deviation is $5.00. The owner takes a sample of 64 bills. What is the probability the mean of his sample will be between $70.00 and $80.00?"

Respuesta :

Answer:

p=1

Step-by-step explanation:

Given that a day care program has an average daily expense of $75.00. The standard deviation is $5.00.

Sample size = 64

Std error of sample = [tex]\frac{5}{\sqrt{64} } \\=0.625[/tex]

Thus sample mean will follow normal with

(75, 0.625)

Required probability

=[tex]P(70<\bar x <80)\\\\= P(|z|<16)\\=1[/tex]

It is almost a certain event with p =1

Answer:

their you go i had it wrong so thought i give someone the right answer

Step-by-step explanation:

1.0

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1.0

34

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