A young sumo wrestler decided to go on a special diet to gain weight rapidly. He gained weight at a constant rate.

The table compares the wrestler's weight (in kilograms) and the time since he started his diet (in months).

How fast did the wrestler gain weight?

___ kilograms per month

A young sumo wrestler decided to go on a special diet to gain weight rapidly He gained weight at a constant rate The table compares the wrestlers weight in kilo class=

Respuesta :

The wrestler gained 5.20 kilograms per month.

Step-by-step explanation:

Let,

x be the weight gained every month.

y be the original weight before weight gain.

According to given statement;

0.5x+y=80.6   Eqn 1

2x+y=88.4    Eqn 2

3.5x+y=96.2    Eqn 3

Subtracting Eqn 1 from Eqn 2

[tex](2x+y)-(0.5x+y)=88.4-80.6\\2x+y-0.5x-y=7.8\\1.5x=7.8[/tex]

Dividing both sides by 1.5

[tex]\frac{1.5x}{1.5}=\frac{7.8}{1.5}\\x=5.20[/tex]

The wrestler gained 5.20 kilograms per month.

Keywords: linear equation, subtraction

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Answer:

5.2 Kilograms

Step-by-step explanation:

On the table, the Time side gets greater by 1.5 each time, and on the weight side it gets bigger by 7.8 .

Since it's asking for kilograms per month, then you need to find the constant rate, which is x kilograms per 1 month. If he gained 7.8 kilograms in 1.5 months, then you divide 7.8 by 1.5, and that will get you 5.2 kilograms per month.