Answer:
y =5e^{2x}
Step-by-step explanation:
Given that a curve passes through the point (0, 5) and has the property that the slope of the curve at every point P is twice the y-coordinate of P.
Let y =f(x) be the equation of the curve
Since slope = 2y
we have
[tex]\frac{dy}{dx}= 2y\\\\y' = 2dx\\ln y = 2x+C\\y = Ae^{2x}[/tex]
To find A
It passes through (0,5)
Substitute x=0 and y=5
5=A
SO equation is
[tex]y =5e^{2x}[/tex]