A system does 1.80×10^{8}J of work while 7.50×10^{8}J of heat transfer occurs to the environment. What is the change in internal energy of the system assuming no other changes (such as in temperature or by the addition of fuel)? (answer in ×10^{8}J)

Question

contestada

Respuesta :

wagonbelleville wagonbelleville · Answer 1 · 2019-12-11T05:31:27+01:00

Answer:

ΔU = -9.30 x 10⁸ J

Explanation:

given,

Work done of the system (W)= 1.8 x 10⁸ J

heat transfer to the environment (ΔQ)= 7.50 × 10⁸ J

Using first law of thermodynamics

ΔQ = ΔU + ΔW

In the case heat is given to the system so the heat transfer is negative.

-7.50 × 10⁸ = ΔU + 1.8 x 10⁸

ΔU = -7.50 × 10⁸ - 1.8 x 10⁸

ΔU = -9.30 x 10⁸ J

Hence, the change in internal energy is equal to -9.30 x 10⁸ J

okpalawalter8 okpalawalter8 · Answer 2 · 2022-03-25T13:35:24+01:00

The change in internal energy of the system is mathematically given as

dU = -9.30 x 10^8 J

Question Parameters:

the system does 1.80×10^{8}J of work while 7.50×10^{8}J of heat transfer

Generally, the equation for the first law of thermodynamics is mathematically given as

dQ = ΔU + dW

Therefore

-7.50 × 10^8 = dU + 1.8 x 10^8

dU = -7.50 × 10^8 - 1.8 x 10^8

dU = -9.30 x 10^8 J