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Calculate the number of grams of carbon dioxide produced from complete combustion of one liter of octane by placing the conversions in the correct order. Make sure the units of adjacent conversion factors cancel out. 1 L Octane times times times times times = 2171 g Carbon Dioxide

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The number of grams of carbon dioxide produced from complete combustion of one liter of octane is; 15.71 grams of CO2.

The balanced equation for the complete combustion of octane is as follows;

  • 2C8H18 + 25O2 ==> 16CO2 + 18H2O.

Recall, the volume of a gas under standard condition is 22.4L

  • Molar mass of CO2 = (12 + (16×2)) = 44

According to the balanced equation;

2 moles of octane gas yields 16 moles of CO2.

In essence;

44.8 L of octane = 704 grams of CO2.

1 L of octane = (1 × 704)/44.8 grams of CO2

= 15.71 grams of CO2.

Therefore, the number of grams of carbon dioxide produced from complete combustion of one liter of octane is; 15.71 grams of CO2.

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