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Answer:

(C)(x + 4)(x + 5)

Step-by-step explanation:

The given equation in the form of polynomial is:

[tex]x^2+9x+20[/tex]

Factorizing the above given equation, we get

[tex]x^2+5x+4x+20[/tex]

[tex]x(x+5)+4(x+5)[/tex]

Taking x+5 common, we have

[tex](x+4)(x+5)[/tex]

which is the required factorised form.

Therefore the factors of the given polynomial are [tex](x+4)(x+5)[/tex].

Thus, Option (C) is correct.

johanrusli

The factored form of the polynomial x² + 9x + 20 is ( x + 4 ) ( x + 5 )

Further explanation

Discriminant of quadratic equation ( ax² + bx + c = 0 ) could be calculated by using :

D = b² - 4 a c

From the value of Discriminant , we know how many solutions the equation has by condition :

D < 0 → No Real Roots

D = 0 → One Real Root

D > 0 → Two Real Roots

Let us now tackle the problem!

Given :

[tex]x^2 + 9x + 20[/tex]

To factor this form, we first look for the following operations:

_ + _ = 9

_ × _ = 20

To fill in the blanks, the matching numbers are :

4 + 5 = 9

4 × 5 = 20

Next, the above equation can be factorized into:

[tex]x^2 + 9x + 20[/tex]

[tex]x^2 + 4x + 5x + 20[/tex]

[tex](x^2 + 4x) + (5x + 20)[/tex]

[tex]x(x + 4) + 5(x + 4)[/tex]

[tex]\large {\boxed {(x + 4)(x + 5)} }[/tex]

Learn more

  • Solving Quadratic Equations by Factoring : https://brainly.com/question/12182022
  • Determine the Discriminant : https://brainly.com/question/4600943
  • Formula of Quadratic Equations : https://brainly.com/question/3776858

Answer details

Grade: High School

Subject: Mathematics

Chapter: Quadratic Equations

Keywords: Quadratic , Equation , Discriminant , Real , Number

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