Respuesta :
Answer:
Bond length of HBr = 141 pm
Explanation:
[tex]\% \ ionic\ character=\frac{measured\ dipole\ moment}{dipole\ moment\ of\ 100\% ionic\ compound(\mu_(ionic))} \times 100 \%[/tex]
measured dipole moment of HBr = 0.851 D
[tex]1D=3.34\times 10_^{-30}C.m[/tex]
therefore,
dipole moment of HBr in C.m is,
[tex]0.851D\times (\frac{3.34\times 10^{-30}C.m}{1D} )=2.84 \times 10^{-30} C.m[/tex]
dipole moment is related with charge and bond length as follows:
[tex]\mu_{ionic}=Q\times r[/tex]
Here Q is charge and r is interatomic distance or bond length
In case of HBr, Q is 1.6×10^-19 C.
Calculate diople moment HBr, [tex]\mu_(ionic)[/tex] as follows:
[tex]12.6=\frac{2.84\times 10^{-30}C.m}{\mu_{ionic}}\times 100 \\\mu_{ionic}=\frac{2.84\times 10^{-30}C.m}{12.6}\times 100\\\mu_{ionic}=Q\times r\\2.25 \times 10^{-29}C.m=1.6 \times 10^{-19}C \times r\\r=1.41\times 10^{-10}m\\=141pm[/tex]
Bond length of HBr is 141 pm
