Answer:
The de Broglie wavelength associated with a baseball is[tex]9.763\times 10^{-26} nm[/tex].
Explanation:
De-Broglie wavelength is calculated by using the formula:
[tex]\lambda=\frac{h}{mv}[/tex] .....(1)
where,
[tex]\lambda[/tex] = wavelength of particle
h = Planck's constant = [tex]6.626\times 10^{-34}Js[/tex]
m = mass of particle
v = velocity of particle
We have :
m = 220 g =0.220 kg
velocity of the baseball , v= 69 mile/h
1 mile = 1609.34 m , 1 hour = 3600 s
v = [tex]\frac{69\times 1609.34 m}{3600 s}=30.85 m/s[/tex]
[tex]\lambda=\frac{6.626\times 10^{-34}Js}{0.220 kg\times 30.85 m/s}[/tex]
[tex]\lambda =9.763\times 10^{-35} m= 9.763\times 10^{-26} nm[/tex]
([tex]1 m = 10^9 nm[/tex])
The de Broglie wavelength associated with a baseball is[tex]9.763\times 10^{-26} nm[/tex].
