Connor has 14 quarters and 28 dimes.
Step-by-step explanation:
Given,
Worth of coins = $6.30 = 6.30*100 = 630 cents
We know that,
1 quarter = 25 cents
1 dime = 10 cents
Let,
Quarter = x
Dime = y
According to given statement;
25x+10y=630 Eqn 1
The number of dimes is 14 more than the number of quarters
y = x+14 Eqn 2
Putting value of y from Eqn 2 in Eqn 1
[tex]25x+10(x+14)=630\\25x+10x+140=630\\35x=630-140\\35x=490[/tex]
Dividing both sides by 35
[tex]\frac{35x}{35}=\frac{490}{35}\\x=14[/tex]
Putting x=14 in Eqn 2
[tex]y=14+14\\y=28[/tex]
Connor has 14 quarters and 28 dimes.
Keywords: linear equation, substitution method
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