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Consider the reaction between iron (III) oxide, Fe2O3 and carbon monoxide, CO. Fe2O3 + 3CO --> 2Fe + 3CO2 In the process, 213 g of Fe2O3 are reacted with 140 of CO. (a) calculate mass of Fe formed (b) how many moles of the excess reagent is left at the end of the reaction? Pls show me how to calculate this using dimensional analysis :(

Respuesta :

To calculate the mass of Fe formed in a) we get first the limiting reactant between Fe2O3 and CO. Given the masses, the ratio of Fe2O3 is 1.33 while that of CO is 1.67. Hence the limiting reagent is Fe2O3. The mass of Fe formed is 148.98 grams. In b, the needed CO is only 112.04 grams. Hence, the excess is 27. 96 grams. 

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