When KOH and Cu(NO3)2 are mixed it yields copper(II) hydroxide and potassium nitrate. The balanced reaction is:
Cu(No3)2(aq) + 2 KOH(aq)
= Cu(OH)2(s) + 2 KNo3(aq)
As we can see from the equation a solid is formed therefore a
precipitate is formed which is the copper (II) hydroxide which has a blue to
purple appearance. This can be observed since copper
(II) hydroxide has a low
solubility in aqueous solution.
