Answer:
The force that the output plunger applies to the car is: 5535 N.
Explanation:
We need to remember the equation that relate force and pressure is:[tex]P=\frac{F}{A}[/tex]. Now we want to determine the force applied to the car, so taking acount that the difference in height of input piston with the output plunger is neglected, we can get:[tex]\frac{F_{2} }{A_{2} } =\frac{F_{1} }{A_{1} }[/tex] and solving for the F2:[tex]\frac{F_{2} }{F_{1} } =\frac{A_{2} }{A_{1} }=\frac{\pi*r_{2} ^{2}}{\pi*r_{1} ^{2}}[/tex], replacing the values given we obtain the force as:[tex]F_{2}=F_{1}*(\frac{r_{2} }{r_{1}} )^{2} =(64)*(9.3)^{2} =5535(N)[/tex]
