Answer:
Weight=6040.8lbf
pressure=1.7445PSI
Exp9lanation:
Hello! To solve this problem use the following steps
1. Find the volume occupied by the water using the equation to calculate the volume of a cylinder
D= diamater=6ft
h=height=3.4ft
V=volume
[tex]V=\frac{\pi }{4} d^2 h=\frac{\pi }{4} (6^2)(3.4)=96.13ft^3[/tex]
2. The density of water at normal conditions is 62.4 lbm / ft ^ 3, remember that the mass is the product of the volume by density.
m=v(density)
m=(96.13)(62.4)=5998.68lbm=186.4slug
to find the weight you multiply by gravity (32.2ft / s ^ 2)
W=mg=186.4slug(32.4ft/S^2)=6040.8lbf
3. Manometric pressure is the pressure at the bottom of the tank due exclusively to water, it is equal to the product of gravity (32.2ft / s ^ 2) density and height
[tex]P=(32.2)(62.4)(3.4)=6831.55\frac{ lbm ft}{s^2 ft^2} =1.7445PSI[/tex]
