20 PTS!!!
Math pls help
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Answer:
The answer to your question is: 30 u²
Step-by-step explanation:
Process
1.- Calculate the length of the base and the length of the height
dAB = [tex]\sqrt{(x2-x1)^{2} + (y2 - y1)^{2} }[/tex]
dAB = [tex]\sqrt{(5+ 3)^{2} + (1 - 5)^{2} }[/tex]
dAB = [tex]\sqrt{8^{2} + (-4)^{2} }[/tex]
dAB = [tex]\sqrt{64 + 16}[/tex]
dAB = [tex]\sqrt{80}[/tex]
dCD = [tex]\sqrt{(x2-x1)^{2} + (y2 - y1)^{2} }[/tex]
dCD = [tex]\sqrt{(-4 + 1)^{2} + (-2 - 4)^{2} }[/tex]
dCD = [tex]\sqrt{(-3)^{2} + (-6)^{2} }[/tex]
dCD = [tex]\sqrt{9 + 36}[/tex]
dCD = [tex]\sqrt{45}[/tex]
Area of a triangle = base x height / 2
= [tex]\frac{\sqrt{80} \sqrt{45} }{2}[/tex]
[tex]= \frac{\sqrt{3600} }{2}[/tex]
[tex]= \frac{60}{2}[/tex]
= 30 u²