Answer:
The rate of heat conduction out of the human body is: 159.6(J/s)
Explanation:
We need to apply the thermal conduction equation ([tex]\frac{Q}{t} =\frac{K*A*(T_{2}-T_{1}) }{L}[/tex]), where Q is heat, t is time, K is the thermal conductivity constant of the material, A is the surface area of transfer heat, T is temperature and L is the distance of the "wall" between the differents temperatures (see attached), it's used because the tissues are in direct contact between them. Now we need to know that Q/t is the rate of heat conduction so replacing the values given, we get: [tex]\frac{Q}{t}=\frac{0.2*1.9*(32.8-37)}{0.01} =-159.6(J/s)[/tex], the negative sign means the heat is outing of the body, so the rate of heat conduction out of the human body will be: 159.6(J/s).
