Answer:
Mass = 0.048 g
Explanation:
Given data:
Temperature =22 °C (273+ 22 = 296K)
Pressure = 742 mmHg (742/760 = 0.98 atm)
Volume = 43.5 mL ( 0.044 L)
Mass of magnesium = ?
Solution:
PV = nRT
n = PV/RT
n = 0.98 atm × 0.044 L / 0.0821 atm. L. mol⁻¹. K⁻¹ × 296K)
n = 0.043 atm. L / 24.3 atm. L. mol⁻¹
n = 0.002 mol
Mass of Mg:
Mass = number of moles × molar mass
Mass = 0.002 mol × 24 g/mol
Mass = 0.048 g
