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Two jets leave an air base at the same time and travel in opposite directions. One jet travels 94 mi/h slower than the other. If the two jets are 2956 miles apart after two hours, what is the rate of change?

Respuesta :

znk

Answer:

1478 mi/h  

Step-by-step explanation:

The rate of change is the distance divided by the time.

[tex]\text{Rate of change} = \dfrac{\text{distance}}{\text{time}} = \dfrac{\text{2956 mi}}{\text{2 h}} = \textbf{1478 mi/h}[/tex]

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